zaimovicsven23 zaimovicsven23
  • 22-04-2022
  • Mathematics
contestada

need help with question 16

need help with question 16 class=

Respuesta :

devishri1977
devishri1977 devishri1977
  • 22-04-2022

Answer:

C)

Step-by-step explanation:

u =  x + 1

u - 1 = x

[tex]\int\limits {\dfrac{x}{\sqrt{x+1}}} \, dx = \int\limits {\dfrac{u-1}{\sqrt{u}}} \, du \\\\[/tex]

                   [tex]=\int {\left(\dfrac{u}{u^{\frac{1}{2}}}-\dfrac{1}{u^{\frac{1}{2}}} \right )\, du \\\\ = \int {u^{1-\frac{1}{2}}-1*u^{\frac{-1}{2}}} \, du\\\\ =\int {(u^{\frac{1}{2}}-u^{\frac{-1}{2}})} \, du[/tex]

Answer Link

Otras preguntas

using special products what is (wx-y)^2
How are Poland, Hungary and Serbia different ?
Is 6/5 greater or less than 3/3
Explain why cells don't just continue to grow larger as organisms grow larger.
An artificial lake is in the shape of a rectangle and has an area of 9/20 square mile. The width of the lake is 1/5 the length of the lake. What are the dimensi
What are the factors of -72 that add up to -15
Todd is using the benchmark 1/2 to compare fractions. Which statement is not correct. A 5/6 less than a 1/2
What is 1/3 of $55,000.00
using special products what is (wx-y)^2
If there is a sexually-transmitted disease"AIDS", how to cure it?