[tex]\qquad\qquad\huge\underline{{\sf Answer}}[/tex]
Let's solve ~
[tex]\qquad \tt \dashrightarrow \:6 < 4x + 8 < 14[/tex]
[tex]\qquad \tt \dashrightarrow \:6 - 8 < 4x + 8 - 8 < 14 - 8[/tex]
[tex]\qquad \tt \dashrightarrow \: - 2 < 4x < 6[/tex]
[tex]\qquad \tt \dashrightarrow \: \dfrac{ - 2}{4} < \dfrac{4x}{4} < \dfrac{6}{4} [/tex]
[tex]\qquad \tt \dashrightarrow \: \dfrac{ - 1}{2} < {x}{} < \dfrac{3}{2} [/tex]
hope it helps ~
