Seudónimo Seudónimo
  • 23-04-2022
  • Mathematics
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helloooo can someone help meeeeeeeee

helloooo can someone help meeeeeeeee class=

Respuesta :

igoroleshko156
igoroleshko156 igoroleshko156
  • 23-04-2022

Answer:

Option B, [tex](48x^{8}y^{5})[/tex]

Step-by-step explanation:

Step 1:  Simplify the exponent

[tex](12x^{2}y^{3})(2x^{3}y)^{2}[/tex]

[tex](12x^{2}y^{3})(2^{2}x^{3*2}y^{1*2})[/tex]

[tex](12x^{2}y^{3})(4x^{6}y^{2})[/tex]

Step 2:  Simply the expression

[tex](12x^{2}y^{3}*4x^{6}y^{2})[/tex]

[tex](48x^{2+6}y^{3+2})[/tex]

[tex](48x^{8}y^{5})[/tex]

Answer: Option B, [tex](48x^{8}y^{5})[/tex]

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