Talitakumi
Talitakumi
26-04-2022
Physics
contestada
Guys i need help rn
Needs a nice ans, thanks
Respuesta :
Аноним
Аноним
26-04-2022
Answer:
51.92 m
Explanation:
Given
angle at which it is launched (α) = 30°
initial velocity (v₀) = 31.9 m/s
Formula
Range (R) = [tex]\frac{v_{0}^{2} sin2\alpha }{g}[/tex]
Solving for R
R = (31.9)² x sin2(30°) / 9.8
R = 1017.61 x sin60° / 9.8
R = 1017.61 / 19.6
[sin 60° = 1/2]
R =
51.92 m
Answer Link
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