Given,
-116 = -2(6v+8)-4
Solving for v ,
=> -116 = -12v-16-4 (expanding)
=> -116+16+4 = -12 v (transposing right hand term to left hand term , and changing sign)
=> -96 = -12 v
Cancelling minus sign in both sides ,
=> v = 96/12
=> v = 8
Hence the value of v is [tex]\fbox{8}[/tex].
