yosussybakaka yosussybakaka
  • 22-09-2022
  • Mathematics
contestada

pls answer these two questions ASAP​

pls answer these two questions ASAP class=

Respuesta :

sangers1959 sangers1959
  • 22-09-2022

Answer:

Step-by-step explanation:

[tex]\displaystyle\\\frac{10px^2}{3c^2d} \div\frac{5px}{6c^2d^2} =\\\\\frac{10px^2}{3c^2d}*\frac{6c^2d^2}{5px} =\\\\\frac{60c^2d^2px^2}{15c^2dpx^2} =\\\\4d\\\\\\\frac{3}{x+7} \div\frac{8x^2-8x}{x^2+6x-7} =\\\\\frac{3}{x+7} \div\frac{8x(x-1)}{x^2-x+7x-7} =\\\\\frac{3}{x+7} \div\frac{8x(x-1)}{x(x-1)+7(x-1)} =\\\\\frac{3}{x+7} \div\frac{8x(x-1)}{(x-1)(x+7)} =\\\\\frac{3}{x+7} \div\frac{8x}{x+7} =\\\\\frac{3}{x+7} *\frac{x+7}{8x} \\\\\frac{3(x+7)}{8x(x+7)}=\\\\\frac{3}{8x}[/tex]

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