30
Given the expression for the instantaneous voltage expressed as:
[tex]v=60\sin \theta[/tex]Given the following parameter:
θ = 30⁰
Substitute the given parameter into the formula to have:
[tex]\begin{gathered} v=60\sin 30^0 \\ v=60(0.5) \\ v=30 \end{gathered}[/tex]Therefore the instantaneous voltage when θ = 30⁰ is 30.
