Respuesta :

SOLUTION

The following is a geometric series

We will use the formula

[tex]T_n=ar^{n-1}[/tex]

Where Tn is the nth term of the series,

n is the number of terms = 8,

a is the first term = 15

And r is the common ratio = 1.2 (to find r, divide the second term, 18 by the first term which is 15

Now let's solve

[tex]\begin{gathered} T_n=ar^{n-1} \\ T_8=15\times1.2^{8-1} \\ T_8=15\times1.2^7 \\ T_8=15\times3.583 \\ T_8=53.748 \end{gathered}[/tex]

So the 8th term = 53.748

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