According to the problem, the can of juice has the form of a cylinder, so we have to use the following formula
[tex]V=\pi(r)^2h[/tex]Where the radius is half the diameter, r = 3 in, h = 5.5 in, and pi = 3.14. Replacing these values, we have
[tex]V=3.14\cdot(3in)^2\cdot5.5in=155.43in^3[/tex]