Respuesta :

[tex]\begin{gathered} d=10 \\ c=5 \\ \text{ find } \\ 5d\div c+2 \\ 5(10)\div5+2 \\ \text{ using pemdas princ}iple \\ 50\div5+2 \\ \frac{50}{5}+2=10+2=12 \end{gathered}[/tex]

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