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To rent a certain meeting room, a college charges a reservation fee of $46 and an additional fee of $6.70 per hour. The math club wants to spend less than$106.30 on renting the meeting room.What are the possible amounts of time for which they could rent the meeting room?Use t for the number of hours the meeting room is rented, and solve your inequality for t.

Respuesta :

As given by the question

There are given that the college charges a reservation fee of $46.

Now,

According to the question, the inequality is:

[tex]46+6.70t<106.30[/tex]

Then,

To solve the above inequality, collect the constant terms on the right side

So,

[tex]\begin{gathered} 46+6.70t<106.30 \\ 6.70t<106.30-46 \\ 6.70t<60.3 \\ t<\frac{60.3}{6.70} \\ t<9 \end{gathered}[/tex]

Hence, the room could be rented for up to 9 hours less than the stated amount.

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