Respuesta :

The number of bacteria in the generation 9 can be determined as,

[tex]\begin{gathered} a(n)=60\times3^{(n-1)} \\ a(9)=60\times3^{(9-1)} \\ =60\times3^8 \\ =393660 \end{gathered}[/tex]

Thus, option (A) is correct.

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