We have the expression:
[tex]6bx-4=-4-10x[/tex]We have to find the value of b so that the solution set is all real numbers for x.
This will happen when the expression is an identity for any value of x.
This happens when:
[tex]\begin{gathered} 6b\cdot x-4=-4-10x \\ 6b\cdot x=-10x \\ 6b=-10 \\ b=-\frac{10}{6}=-\frac{5}{3} \end{gathered}[/tex]When b=-5/3, any real value of x is a solution to the expression.
Answer: b = -5/3.
