Respuesta :

Part a

Remember that the ordinate is the y-coordinate and the abscisa is the x-coordinate

so

(x, 2x+1)

y=2x+1

Part b

[tex](\frac{1}{2}y^2,y)[/tex]

x=(1/2)y^2

Part c

x^2+y^2=25

Part e

y=2

Part f

x=7

Part g

x=y

Part h

[tex]\sqrt[\square]{x^2+y^2}=5[/tex]

Part i

[tex]\sqrt[\square]{(x-2)^2+(y-3)^2}=5[/tex]

Otras preguntas