Respuesta :

PsychrolutesMarcidus
[tex] \frac{2x+4}{3x-3}( \frac{12x-12}{x+5}) [/tex]
=[tex] \frac{2(x+2)}{3(x-1)}( \frac{12(x-1)}{x+5}) [/tex]
=[tex] \frac{2(x+2)4}{x+5} [/tex]
=[tex] \frac{8(x+2)}{x+5} [/tex]

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[tex] \frac{x^2-16}{2x-8}[/tex]÷ [tex] \frac{x-4)^2}{8x-32}[/tex]
=[tex] \frac{x^2-16}{2x-8}[/tex]( [tex] \frac{8x-32}{x-4)^2}[/tex])
=[tex] \frac{(x-4)^2}{2x-8}[/tex]( [tex] \frac{8x-32}{x-4)^2}[/tex])
=[tex] \frac{1}{2x-8}[/tex]( [tex] \frac{8x-32}{1}[/tex])
=[tex] \frac{8x-32}{2x-8}[/tex]
=[tex] \frac{8(x-4)}{2(x-4)}[/tex]
=[tex] \frac{4(x-4)}{1(x-4)}[/tex]
=4
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[tex] \frac{1}{3x}[/tex]
= (3x)⁻¹

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