Answer:
[tex]m=22.30g[/tex]
Explanation:
Hello,
In this case, by knowing the volume of acetone and searching for its density, which is about 0.784 g/mL, we compute the mass as shown below:
[tex]\rho =\frac{m}{V}\\\\m=\rho *V=0.784\frac{g}{mL}*28.44mL}\\\\m=22.30g[/tex]
Best regards.
