Suppose That the length of a certain rectangular is 1 meter more than 5 times it width. The perimeter of rectangular is 98 meters. Find the length and width
Let breadth(b) of rectangular be x Then length(l) = 5x + 1 We have : perimeter(p) =2(l+b) Or, p = 2 (5x+1+x) p = 2 (6x+ 1) p = 12x + 2 Given that p= 98 m 98=12x+2 i.e. x= 8 So breadth b= 8m and length l =5*8+1= 41m
