[tex]\bf \textit{ vertex of a vertical parabola, using coefficients}\\\\
\begin{array}{llccll}
y = &{{ 1}}x^2&{{ +4}}x&{{ +1}}\\
&\uparrow &\uparrow &\uparrow \\
&a&b&c
\end{array}\qquad
\left(-\cfrac{{{ b}}}{2{{ a}}}\quad ,\quad {{ c}}-\cfrac{{{ b}}^2}{4{{ a}}}\right)[/tex]
the squared variable is the "x", thus is a vertical parabola, thus, the axis of symmetry will occur over the x-coordinate of the vertex, and thus will be [tex]\bf x=-\cfrac{{{ b}}}{2{{ a}}}[/tex]
