mugegs2015
mugegs2015
26-07-2017
Mathematics
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...Help Please...question in the file.
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Banabanana
Banabanana
26-07-2017
[tex]3^{-3}= \frac{1}{3^3}= \frac{1}{27} \\ \\ 3^{-2}= \frac{1}{3^2}= \frac{1}{9} \\ \\ 3^{-1}= \frac{1}{3^1}= \frac{1}{3} \\ \\3^{0}=1 \\\\ 3^1=3\\\\3^2=9\\\\3^3=27[/tex]
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