a speeding car traveling north at 80mph passes the tramway intersection when the police begin pursuit. The police start 6 miles south of tramway traveling at 100mph. How many miles north of tramway will they be when they catch up with the speeding car?
Define x = distance, miles, that the speeding car travels before the police catch up. t = time, hrs, before the police catch up. Then (80 m/h)*(t h) = (x mi) 80t = x (1)
(100 mi/h)*(t h) = (x+6 mi) 100t = x + 6 (2)
Subtract (1) from (2). 100t - 80t = x+6 - x 20t = 6 t = 6/20 = 0.3 h
