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What is the y-intercept of the equation of the line that is perpendicular to the line y = x + 10 and passes through the point (15, –5)?

The equation of the line in slope-intercept form is y = x +

Respuesta :

choixongdong
y = x + 10 has slope = 1
perpendicular lines, slope is opposite and reciprocal
so perpendicular line slope = -1
passes through the point (15, –5)
y = mx + b 
-5 = -1(15) + b
b = -5 + 15
b = 10 
y -intercept : 10

The equation of the line in slope-intercept form is y = -x + 10

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