PutBackAngel
PutBackAngel
22-09-2015
Mathematics
contestada
[tex] \frac{y2}{y7} [/tex]
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TSO
TSO
22-09-2015
[tex] \frac{y^2}{y^7} =y^{2-7} =y^{-5 } = \boxed {\frac{1}{y^5} }[/tex]
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