lexinerd
lexinerd
22-06-2014
Mathematics
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Can someone please answer this
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konrad509
konrad509
22-06-2014
[tex]100\ ft\approx0.3\ m\\ 0.3=-16t^2+100\\ 16t^2=99.7\\ t^2\approx6.23\\ t\approx-2.5 \vee t\approx2.5 \Rightarrow B [/tex]
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