ΔT= T (solvet freezing point)-T (solution) =T(water freezing point)-T(solution)
ΔT =0⁰C - T(solution)
ΔT=[tex] K_{f} *m[/tex]
molality =(number mol solute)/kg solvent = 0.31mol/0.175 kg =(0.31/0.175)m
K(f water)=1.86⁰C/m
ΔT=1.86⁰C/m*(0.31/0.175)m=3.29⁰C
T(solution) =0⁰C - 3.29⁰C =3.29⁰C
